Print value and address of pointer defined in function?

Question

I think this is a really easy thing to code, but I\'m having trouble with the syntax in C, I\'ve just programmed in C++.

#include 
#include 

        

Answer 1

Address are some memory values which are written in hexadecimal notation starting with 0x

/Value pointed to by the pointer iptr/

printf("Value is: %i", *iptr);

Address pointed to by the pointer will be the value of the iptr pointer itself

/print the address pointed to by the iptr/

 printf("Address is: %p", iprt);

/print the address of iptr itself/

 printf("Address of iptr: %p", &iptr )