Print value and address of pointer defined in function?

Question

I think this is a really easy thing to code, but I\'m having trouble with the syntax in C, I\'ve just programmed in C++.

#include 
#include 

        

Answer 1

int* iptr is already a pointer, so you don't need the & in front of it when you write

printf("Address of iptr variable: %x\n", &iptr );

This is how to print a pointer value.

printf("Address of iptr variable: %p\n", (void*)iptr);

Also you have the function prototype for pointerFuncA() in the wrong place, being inside main(). It should be outside of any function, before it is called.