Remove elements by index in haskell

Question

I\'m new in haskell and I\'m looking for some standard functions to work with lists by indexes.

My exact problem is that i want to remove 3 elements after every 5. If i

Answer 1

Here is my solution:

remElements step num=rem' step num
    where rem' _ _ []=[]
          rem' s n (x:xs)
              |s>0 = x:rem' (s-1) num xs
              |n==0 = x:rem' (step-1) num xs
              |otherwise= rem' 0 (n-1) xs

example:

*Main> remElements 5 3 [1..20]
[1,2,3,4,5,9,10,11,12,13,17,18,19,20]