flow generic type for function [removed]arrow functions)

Question

I usually try to keep flow function types separate from their implementation. It\'s a slightly more readable when I write:

type Fn = string => string;
const a         


        

Answer 1

So I have noticed that if I use bounded generics, it'll work:

type H = (input: T) => T;
const h:H<*> = i => i;

const a: string = h('apple');      // √
const b: number = h(7);            // √
const c: {} = h({ nane: 'jon' });  // √

Don't ask me WHY.