Convert string from __DATE__ into a time_t

Question

I\'m trying to convert the string produced from the __DATE__ macro into a time_t. I don\'t need a full-blown date/time parser, something that only han

Answer 1

Basing on the description given at gcc.gnu.org the build date can be obtain at the compilation time using following macros.

#define BUILDTM_YEAR (\
    __DATE__[7] == '?' ? 1900 \
    : (((__DATE__[7] - '0') * 1000 ) \
    + (__DATE__[8] - '0') * 100 \
    + (__DATE__[9] - '0') * 10 \
    + __DATE__[10] - '0'))

#define BUILDTM_MONTH (\
    __DATE__ [2] == '?' ? 1 \
    : __DATE__ [2] == 'n' ? (__DATE__ [1] == 'a' ? 1 : 6) \
    : __DATE__ [2] == 'b' ? 2 \
    : __DATE__ [2] == 'r' ? (__DATE__ [0] == 'M' ? 3 : 4) \
    : __DATE__ [2] == 'y' ? 5 \
    : __DATE__ [2] == 'l' ? 7 \
    : __DATE__ [2] == 'g' ? 8 \
    : __DATE__ [2] == 'p' ? 9 \
    : __DATE__ [2] == 't' ? 10 \
    : __DATE__ [2] == 'v' ? 11 \
    : 12)

#define BUILDTM_DAY (\
    __DATE__[4] == '?' ? 1 \
    : ((__DATE__[4] == ' ' ? 0 : \
    ((__DATE__[4] - '0') * 10)) + __DATE__[5] - '0'))