i\'m just created a java project to print string that is given in rows and column just like matrix. Here\'s the output that i just made:
h e l l o
_ w o r l
d _
Probably I'll add my answer too, idea is to flatten a two dimensional array to 1d and use the 1D array and transform it to a 2D spiral array. Hope it helps.
Code:
class Test {
static String[][] spiralPrint(int m, int n, String[] a) {
String[][] output = new String[m][n];
int count = 0;
int i, k = 0, l = 0;
while (k < m && l < n) {
for (i = l; i < n; ++i) {
output[k][i] = a[count++];
}
k++;
for (i = k; i < m; ++i) {
output[i][n - 1] = a[count++];
}
n--;
if (k < m) {
for (i = n - 1; i >= l; --i) {
output[m - 1][i] = a[count++];
}
m--;
}
if (l < n) {
for (i = m - 1; i >= k; --i) {
output[i][l] = a[count++];
}
l++;
}
}
return output;
}
private static String[] flattenArray(String[][] input, int m, int n) {
String[] output = new String[m * n];
int k = 0;
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
output[k++] = input[i][j];
}
}
return output;
}
public static void main(String[] args) {
String[][] input = {
{"h", "e", "l", "l", "o"},
{"_", "w", "o", "r", "l"},
{"d", "_", "i", "t", "s"},
{"_", "b", "e", "a", "u"},
{"t", "i", "f", "u", "l"}};
int m = 5;
int n = 5;
String[] flattenArray = flattenArray(input, m, n);
String[][] spiralArray = spiralPrint(m, n, flattenArray);
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
System.out.print(spiralArray[i][j] + " ");
}
System.out.println();
}
}
}
Output:
h e l l o
_ b e a _
s u l u w
t f i t o
i _ d l r
Note: Indeed that I followed this Spiral transform to 1D, but it is not straight forward, I have re-modified to fit to the problem.