Why does `{} == null` give a SyntaxError? [duplicate]

Answer 1

There are two main contexts when parsing code: the expression context and the statement context. The body of a function for example is a statement context, the right side of an assignment is an expression context. To distinguish both makes sense to forbid things like:

 if( if(true) ) alert("nonsense");

Now REPL have a really difficult task: On the one hand, they have to parse functions and codeblocks that get entered, and on the other hand you sometimes just want to check how a certain object look like. Therefore this:

 { a: 1, b: 2 }

is actually a SyntaxError in JavaScript, as a { in a statement context starts a block of code, and : is invalid then. However the REPL is clever enough and puts that object into an expression context, and evaluates it as if it would be in parens:

({ a: 1, b: 2 })

the same happens for:

 {} == {}

which is actually also a SyntaxError, however the REPL also moves it into an expression context:

 ({} == {})

That "moving into an expression context" is a complicated task, and it seems as if the REPL just does not see the expression here:

 {} == null

and therefore parses {} as a block. Thats the case because the REPL just naively checks if the first and the last character are { and }, which is the case for {} == {} but not for {} == null.

Relevant part of the chromium sourcecode:

 if (/^\s*\{/.test(text) && /\}\s*$/.test(text))
  text = '(' + text + ')';

executionContext.evaluate(text, "console", !!useCommandLineAPI, false, false, true, printResult);