PHP: How to instantiate a class with arguments from within another class

Question

I am in a situations where i need to instantiate a class with arguments from within an instance of another class. Here is the prototype:

//test.php

class test
{         


        

Answer 1

You can:

1) Modify test class to accept an array, which contains the data you wish to pass.

//test.php

class test
{
        function __construct($a)
        {
                echo $a[0] . '
';
                echo $a[1] . '
';
                echo $a[2] . '
';
        }
}

2) initiate using a user method instead of the constructor and call it using the call_user_func_array() function.

//test.php

class test
{
        function __construct()
        {

        }

        public function init($a, $b, $c){
                echo $a . '
';
                echo $b . '
';
                echo $c . '
';
        }

}

In your main class:

class myclass
{
function cls($file_name, $args = array())
{
        include $file_name . ".php";

        if (isset($args))
        {
                // this is where the problem might be, i need to pass as many arguments as test class has.
                $class_instance = new $file_name($args);
                call_user_func_array(array($class_instance,'init'), $args);
        }
        else
        {
                $class_instance = new $file_name();
        }

        return $class_instance;
}
}

http://www.php.net/manual/en/function.call-user-func-array.php

Lastly, you can leave your constructor params blank and use func_get_args().

//test.php

class test
{
        function __construct()
        {
                $a = func_get_args();
                echo $a[0] . '
';
                echo $a[1] . '
';
                echo $a[2] . '
';
        }
}

http://sg.php.net/manual/en/function.func-get-args.php