void cast of argc and argv

Question

I\'m looking at a piece of C++ code, and the first line in the main function caught my attention:

int main(int argc, const char* argv[]) {
    (void)argc; (void)         


        

Answer 1

If you set -Werror option, the compiler makes all warnings into errors, stopping compilation. It's a good practice set -Wall -Werror to check all inconsistences.