How to see if the list contains consecutive numbers

Question

I want to test if a list contains consecutive integers and no repetition of numbers. For example, if I have

l = [1, 3, 5, 2, 4, 6]

It should re

Answer 1

1.

l.sort()

2.

for i in range(0,len(l)-1)))
   print(all((l[i+1]-l[i]==1)