How to see if the list contains consecutive numbers

Question

I want to test if a list contains consecutive integers and no repetition of numbers. For example, if I have

l = [1, 3, 5, 2, 4, 6]

It should re

Answer 1

The input to this function is your list.This function returns False if the numbers are repeated. The below code works even if the list does not start with 1.

def check_is_consecutive(l):
    """
    sorts the list and 
    checks if the elements in the list are consecutive
    This function does not handle any exceptions.
    returns true if the list contains consecutive numbers, else False
    """
    l = list(filter(None,l))
    l = sorted(l)
    if len(l) > 1:
        maximum = l[-1]
        minimum = l[0] - 1
        if minimum == 0:
            if sum(l) == (maximum * (maximum+1) /2): 
                return True
            else:
                return False
        else:
            if sum(l) == (maximum * (maximum+1) /2) - (minimum * (minimum+1) /2) : 
                return True
            else:
                return False
    else:
        return True