How to see if the list contains consecutive numbers

Question

I want to test if a list contains consecutive integers and no repetition of numbers. For example, if I have

l = [1, 3, 5, 2, 4, 6]

It should re

Answer 1

I split your query into two parts part A "list contains up to n consecutive numbers" this is the first line if len(l) != len(set(l)):

And part b, splits the list into possible shorter lists and checks if they are consecutive.

def example (l, n):
    if len(l) != len(set(l)):  # part a
        return False
    for i in range(0, len(l)-n+1):  # part b
        if l[i:i+3] == sorted(l[i:i+3]):
            return True
    return False

l = [1, 3, 5, 2, 4, 6]
print example(l, 3)