I have another basic question, that I haven\'t been able to find the answer for, but it seems like something that should be easy to do.
Ok, imagine you have a structured
It's not quite a single function call, but the following shows one way to drop the i-th field:
In [67]: a
Out[67]:
array([(1.0, 2.0, 3.0), (4.0, 5.0, 6.0)],
dtype=[('A', '
Wrapped up as a function:
def remove_field_num(a, i):
names = list(a.dtype.names)
new_names = names[:i] + names[i+1:]
b = a[new_names]
return b
It might be more natural to remove a given field name:
def remove_field_name(a, name):
names = list(a.dtype.names)
if name in names:
names.remove(name)
b = a[names]
return b
Also, check out the drop_rec_fields function that is part of the mlab module of matplotlib.
Update: See my answer at How to remove a column from a structured numpy array *without copying it*? for a method to create a view of subsets of the fields of a structured array without making a copy of the array.