PHP regex non-capture non-match group

Question

I\'m making a date matching regex, and it\'s all going pretty well, I\'ve got this so far:

\"/(?:[0-3])?[0-9]-(?:[0-1])?[0-9]-(?:20)[0-1][0-9]/\"

Answer 1

[Edited (again) to improve formatting and fix the intro.]

This is a comment and an answer.

The answer part... I do agree with alex' earlier answer.

1. (?: ), in contrast to ( ), is used to avoid capturing text, generally so as to have fewer back references thrown in with those you do want or to improve speed performance.

2. The ? following the (?: ) -- or when following anything except * + ? or {} -- means that the preceding item may or may not be found within a legitimate match. Eg, /z34?/ will match z3 as well as z34 but it won't match z35 or z etc.

The comment part... I made what might considered to be improvements to the regex you were working on:

(?:^|\s)(0?[1-9]|[1-2][0-9]|30|31)-(0?[1-9]|10|11|12)-((?:20)?[0-9][0-9])(?:\s|$)

-- First, it avoids things like 0-0-2011

-- Second, it avoids things like 233443-4-201154564

-- Third, it includes things like 1-1-2022

-- Forth, it includes things like 1-1-11

-- Fifth, it avoids things like 34-4-11

-- Sixth, it allows you to capture the day, month, and year so you can refer to these more easily in code.. code that would, for example, do a further check (is the second captured group 2 and is either the first captured group 29 and this a leap year or else the first captured group is <29) in order to see if a feb 29 date qualified or not.

Finally, note that you'll still get dates that won't exist, eg, 31-6-11. If you want to avoid these, then try:

(?:^|\s)(?:(?:(0?[1-9]|[1-2][0-9]|30|31)-(0?[13578]|10|12))|(?:(0?[1-9]|[1-2][0-9]|30)-(0?[469]|11))|(?:(0?[1-9]|[1-2][0-9])-(0?2)))-((?:20)?[0-9][0-9])(?:\s|$)

Also, I assumed the dates would be preceded and followed by a space (or beg/end of line), but you may want ot adjust that (eg, to allow punctuations).

A commenter elsewhere referenced this resource which you might find useful: http://rubular.com/