Formatting a list of text into columns

Question

I\'m trying to output a list of string values into a 2 column format. The standard way of making a list of strings into \"normal text\" is by using the string.join

Answer 1

Two columns, separated by tabs, joined into lines. Look in itertools for iterator equivalents, to achieve a space-efficient solution.

import string
def fmtpairs(mylist):
    pairs = zip(mylist[::2],mylist[1::2])
    return '\n'.join('\t'.join(i) for i in pairs)

print fmtpairs(list(string.ascii_uppercase))

A   B
C   D
E   F
G   H
I   J
...

Oops... got caught by S.Lott (thank you).

A more general solution, handles any number of columns and odd lists. Slightly modified from S.lott, using generators to save space.

def fmtcols(mylist, cols):
    lines = ("\t".join(mylist[i:i+cols]) for i in xrange(0,len(mylist),cols))
    return '\n'.join(lines)