How should I define a std::function variable with default arguments?

Question

To set a std::function variable to a lambda function with default argument I can use auto as in:

auto foo = [](int x = 10){cout << x <<          


        

Answer 1

Don't know if that will help you, but you can store a lambda in a templated struct.

template 
struct Bar {
  F foo;
  Bar (F fun): foo (std::move (fun)) {}
};

auto f = [](int x = 10) {cout << x << endl;};
Bar bar (f);
bar.foo();

auto makeFun = [](){return [](int x = 10) {cout << x << endl;};};

Bar bar2 (makeFun());
bar2.foo();