How to remove the first part of a string in bash?

Question

This code will give the first part, but how to remove it, and get the whole string without the first part?

echo \"first second third etc\"|cut -d \" \" -f1
         


        

Answer 1

You can use substring removal for that, no need for external tools:

$ foo="a b c d"
$ echo "${foo#* }"
b c d