I\'ve the following numpy ndarray.
[ -0.54761371 17.04850603 4.86054302]
I want to apply this function to all elements of the array
Function numpy.apply_along_axis
is not good for this purpose.
Try to use numpy.vectorize
to vectorize your function: https://docs.scipy.org/doc/numpy/reference/generated/numpy.vectorize.html
This function defines a vectorized function which takes a nested sequence of objects or numpy arrays as inputs and returns an single or tuple of numpy array as output.
import numpy as np
import math
# custom function
def sigmoid(x):
return 1 / (1 + math.exp(-x))
# define vectorized sigmoid
sigmoid_v = np.vectorize(sigmoid)
# test
scores = np.array([ -0.54761371, 17.04850603, 4.86054302])
print sigmoid_v(scores)
Output: [ 0.36641822 0.99999996 0.99231327]
Performance test which shows that the scipy.special.expit
is the best solution to calculate logistic function and vectorized variant comes to the worst:
import numpy as np
import math
import timeit
def sigmoid_(x):
return 1 / (1 + math.exp(-x))
sigmoidv = np.vectorize(sigmoid_)
def sigmoid(x):
return 1 / (1 + np.exp(x))
print timeit.timeit("sigmoidv(scores)", "from __main__ import sigmoidv, np; scores = np.random.randn(100)", number=25),\
timeit.timeit("sigmoid(scores)", "from __main__ import sigmoid, np; scores = np.random.randn(100)", number=25),\
timeit.timeit("expit(scores)", "from scipy.special import expit; import numpy as np; scores = np.random.randn(100)", number=25)
print timeit.timeit("sigmoidv(scores)", "from __main__ import sigmoidv, np; scores = np.random.randn(1000)", number=25),\
timeit.timeit("sigmoid(scores)", "from __main__ import sigmoid, np; scores = np.random.randn(1000)", number=25),\
timeit.timeit("expit(scores)", "from scipy.special import expit; import numpy as np; scores = np.random.randn(1000)", number=25)
print timeit.timeit("sigmoidv(scores)", "from __main__ import sigmoidv, np; scores = np.random.randn(10000)", number=25),\
timeit.timeit("sigmoid(scores)", "from __main__ import sigmoid, np; scores = np.random.randn(10000)", number=25),\
timeit.timeit("expit(scores)", "from scipy.special import expit; import numpy as np; scores = np.random.randn(10000)", number=25)
Results:
size vectorized numpy expit
N=100: 0.00179314613342 0.000460863113403 0.000132083892822
N=1000: 0.0122890472412 0.00084114074707 0.000464916229248
N=10000: 0.109477043152 0.00530695915222 0.00424313545227