What happens if delete[] p fails?

Question

Suppose I have a pointer to a dynamically allocated array of 10 elements:

T* p = new T[10];

Later, I want to release that array:

Answer 1

Never do that. If there is already an active exception, std::terminate will be called: "Bang, you're dead". Your destructor must. Not. Throw. Resist.

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edit: Relevant section from the Standard (14882 2003), 15.2 Constructors and Destructors [except.dtor] :

15.2.3 The process of calling destructors for automatic objects constructed on the path from a try block to a throw-expression is called “stack unwinding.” [Note: If a destructor called during stack unwinding exits with an exception, terminate is called (15.5.1). So destructors should generally catch exceptions and not let them propagate out of the destructor. —end note]

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Testcase for playing around (in real life, throw something that is derived from std::exception, never throw int or something else!):

    #include 
    int main() {
        struct Foo {
            ~Foo() {
                throw 0; // ... fore, std::terminate is called.
            }
        };

        try {
            Foo f;
            throw 0; // First one, will be the active exception once Foo::~Foo()
                     // is executed, there- ...
        } catch (int) {
            std::cout << "caught something" << std::endl;
        }
    }