I\'m trying to use this and it doesn\'t appear to be working. I\'m guessing it\'s just not an option, but want to confirm. Is this valid?
(if_it_is) ? thats_cool
What you are trying to use is a Ternary Operator. You are missing the else part of it.
You could do something like:
(if_it_is) ? thats_cool() : function(){};
or
(if_it_is) ? thats_cool() : null;
Or, as others have suggested, you can avoid the ternary if you don't care about the else.
if_it_is && thats_cool();
In JavaScript, as well as most languages, these logical checks step from left to right. So it will first see if if_it_is
is a 'trusy' value (true
, 1
, a string other than ''
, et cetera). If that doesn't pass then it doesn't do the rest of the statement. If it does pass then it will execute thats_cool
as the next check in the logic.
Think of it as the part inside of an if statement. Without the if. So it's kind of a shorthand of
if (if_it_is && thats_cool()) { }