Why is abs(0x80000000) == 0x80000000?

Question

I just started reading Hacker\'s Delight and it defines abs(-2³¹) as -2³¹. Why is that?

I tried printf(\"%x\", abs(0x80000000)) on a f

Answer 1

For a 32bit datatype there is no expression of +2^31, because the biggest number is 2^31-1 ... read more about the two's complement ...