How to achieve python's any() with a custom predicate?

Question

>>> l = list(range(10))
>>> l
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> if filter(lambda x: x > 10, l):
...     print \"foo\"
... else:                    


        

Answer 1

Use a generator expression inside of any():

pred = lambda x: x > 10
if any(pred(i) for i in l):
    print "foo"
else:
    print "bar"

This assumes you already have some predicate function you want to use, of course if it is something simple like this you can just use the Boolean expression directly: any(i > 10 for i in l).