Exit gracefully if file doesn't exist

Question

I have following script in Python 3.2.3:

try:
    file = open(\'file.txt\', \'r\')
except IOError:
    print(\'There was an error opening the file!\')
    sys.ex         


        

Answer 1

Using sys.exit() is fine. If you're that concerned with output, you can always add an extra try/except block within your error handling section to catch the SystemExit and stop it from being directed to console output.

try:
    file = open('file.txt', 'r')
except IOError:
    try:
        print('There was an error opening the file!')
        sys.exit()
    except SystemExit:
        #some code here that won't impact on anything