Is size_t the word size?

Question

Is size_t the word size of the machine that compiled the code?

Parsing with g++, my compiler views size_t as an long unsigned int

Answer 1

In the C++ standard, [support.types] (18.2) /6: "The type size_t is an implementation-defined unsigned integer type that is large enough to contain the size in bytes of any object."

This may or may not be the same as a "word size", whatever that means.