Is a += b operator of char implemented same as a = a + b? [duplicate]

Answer 1

In the second case it is the assignment that is failing, not the calculation itself. If you explicitly cast the result in the second line to a char it works fine and indeed the following three lines generate identical IL:

    c += (char)1;
    c = (char)(c + (char)1);
    c = (char)(c + 1);

So yes. There is a difference.

Note in the third line I didn't bother casting the 1 to char since the calculation will just convert it back to an int anyway.