How can I reduce the following bash script?
grep -P \"STATUS: (?!Perfect)\" recess.txt && exit 1
exit 0
It seems like I should be able
The problem with the grep answers is that if the file is empty you also get a clean response, as if the file had a perfect. So personally I gave up on grep for this and used awk.
awk 'BEGIN{ef=2}; /STATUS: Perfect/{ ef=0;}; /STATUS: Busted/{ print;eff=3;}; END{exit (ef+eff)}' a.txt ; echo $?
This has exit status:
0 : Perfect and !Busted
2 : !Perfect and Busted
3 : Perfect and Busted
5 : !Perfect and !Busted