how to pass a variable through the require() or include() function of php?

Question

when I use this:

require(\"diggstyle_code.php?page=$page_no\");

the warning is :failed to open stream: No error in C:\\xampp\\htdocs\\4ajax\\ga

Answer 1

Though this question is old there's another option that I use which is missing from this thread. You can return a function from the required file which accepts the arguments you want to pass along:

return function(array $something) {
    print_r($something);
}

And call it with the arguments when you require it:

require('file.php')(['some', 'data']);

// or:

$context = require('file.php');
$context(['some', 'data']);