How to construct a defaultdict from a dictionary?

Question

If I have d=dict(zip(range(1,10),range(50,61))) how can I build a collections.defaultdict out of the dict?

The only argument

Answer 1

You can construct a defaultdict from dict, by passing the dict as the second argument.

from collections import defaultdict

d1 = {'foo': 17}
d2 = defaultdict(int, d1)

print(d2['foo'])  ## should print 17
print(d2['bar'])  ## should print 1 (default int val )