Algorithm for scissor paper stone

Question

I am using the following method which works but wondering if there is a better algorithm to perform the test. Is there a better way to do it? Doing this in C# but putting syntax

Answer 1

Observation: The user wins if userInput is only one ahead of computerInput (case of (1,2), (2,3)) or lag two (case of (3,1)).

Conversely, if userInput lags one behind computerInput or two ahead, the user loses.

In the modulo 3, the lag one is the same as the advance two. (-1 mod 3 == 2 mod 3 == 2)

int decision = (userInput - computerInput + 3) % 3;
String[] answer = {"Draw", "Win", "Lose"};

return answer[decision];