How to take the parameter from URL scheme.

Question

I am using URL scheme in my iPhone app,from a page I switch user to safari,and a button click from Web page,I am reverting back to app At that time ,some parameters are passed b

Answer 1

Try this code. this ll useful even if you had numbers of parameters and values in url.

NSURL *url = [NSURL URLWithString:@"xyz.com/result.php?data1=1123660801&data2=250072028055&presult=SUCCESS"];

NSURLComponents *components = [NSURLComponents componentsWithURL:url resolvingAgainstBaseURL:NO];
NSArray *queryItems = [components queryItems];

NSMutableDictionary *dict = [NSMutableDictionary new];

for (NSURLQueryItem *item in queryItems)
{
    [dict setObject:[item value] forKey:[item name]];
}