How to get points coordinate position in the face landmark detection program of dlib?

Question

There is one example python program in dlib to detect the face landmark position. face_landmark_detection.py

This program detect the face feature and denote the landmark

Answer 1

I slightly modified the code.

import dlib
import numpy as np
from skimage import io

predictor_path = "shape_predictor_68_face_landmarks.dat"

detector = dlib.get_frontal_face_detector()
predictor = dlib.shape_predictor(predictor_path)

img = io.imread("FDT.jpg")

dets = detector(img)

#output face landmark points inside retangle
#shape is points datatype
#http://dlib.net/python/#dlib.point
for k, d in enumerate(dets):
    shape = predictor(img, d)

vec = np.empty([68, 2], dtype = int)
for b in range(68):
    vec[b][0] = shape.part(b).x
    vec[b][1] = shape.part(b).y

print(vec)

Here is the output

[[1003  575]
 [1005  593]
 [1009  611]
 [1014  627]
 [1021  642]
 [1030  655]
 [1041  667]
 [1054  675]
 [1069  677]
 [1083  673]
 [1095  664]
 [1105  651]
 [1113  636]
 [1120  621]
 [1123  604]
 [1124  585]
 [1124  567]
 [1010  574]
 [1020  570]
 [1031  571]
 [1042  574]
 [1053  578]
 [1070  577]
 [1081  572]
 [1092  568]
 [1104  566]
 [1114  569]
 [1063  589]
 [1063  601]
 [1063  613]
 [1063  624]
 [1050  628]
 [1056  630]
 [1064  632]
 [1071  630]
 [1077  627]
 [1024  587]
 [1032  587]
 [1040  586]
 [1048  588]
 [1040  590]
 [1031  590]
 [1078  587]
 [1085  585]
 [1093  584]
 [1101  584]
 [1094  588]
 [1086  588]
 [1045  644]
 [1052  641]
 [1058  640]
 [1064  641]
 [1070  639]
 [1078  640]
 [1086  641]
 [1080  651]
 [1073  655]
 [1066  656]
 [1059  656]
 [1052  652]
 [1048  645]
 [1059  645]
 [1065  646]
 [1071  644]
 [1083  642]
 [1072  645]
 [1065  647]
 [1059  646]]

And there is another open source project OpenFace, which is based on dlib and describes each point's correlating part in face.

The url of describing image