IPv6 address validation and canonicalization [closed]

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悲&欢浪女 2021-02-06 13:37

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陌清茗 (楼主)

2021-02-06 13:49

i simply went through adhoc approach to check the validity of IPV4 and IPV6 both addressing scheme:here is my code ... corrections are always welcome in my code. and pardon me if my solution is wrong.

#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
using namespace std;
bool check6(string s)
{
    for(int i=0;i '9') && (s[i] < 'a' || s[i]> 'f') && 
           (s[i] < 'A' || s[i] > 'F'))                       
          return false;
    }
    return true;
}
   bool check4(string s)
   {
      for(int i=0; i< s.length(); i++)
      {
       if(!(s[i]>= '0' && s[i] <= '9'))
          return false;
      }
     stringstream ss(s);
      int e;
      ss >> e;
     if( e < 0 || e > 255 )
      return false;
     else
      return true;
   }

int main()
{
  string s;
  cin>>s;
  vector v;
  int i=0;
  int d=0;
  if((s.find(":")!=std::string::npos || 
         s.find("::")!=std::string::npos)&&  
     s.find(".")==std::string::npos)     
   {
      int x=0;
      while(i< s.length())
      {
          string s1 ="";
          while(i< s.length() && s[i]!= ':')
          {
             s1+= s[i];
             i++;
          }
         if(s1!="")
         v.push_back(s1);
         if((i+1)< s.length() && s[i]==':' && s[i+1]==':')
            x++;
         i++;
         if(i< s.length())
         d++;
     }
      if(x > 1 || d > 7 || v.size() > 8 || (x==1 && d >6))
      {
         cout<<"Not Valid"< 2 && v.size() ==0)
      {

         cout<<"Not Valid"< 4)
             {
                    cout<<"Not Valid"< 4 || v.size()> 4)
    {
        cout<<"Not Valid"< 3)
            {
                cout<<"Not Valid"<