How can I use fast FFT-based convolution to implement a LPF if the fast convolution requires a LPF?

Question

I\'m an experienced software engineer with some minor college DSP knowledge. I\'m working on a smartphone application to process signal data, such as from the microphone (sample

Answer 1

No contradiction. X has high frequencies. Y = X*F no longer has high frequencies because F filters (i.e., multiplies) them out.