Python - Zeep SOAP Complex Header

Question

I\'d like to pass \"Complex\" Header to a SOAP service with zeep library

Here\'s what it should look like

Answer 1

Thx Oblivion02.

I finally use a raw method

headers = {'content-type': 'text/xml'}
body = """

FOO
JAM


          ...

"""

response = requests.post(wsdl,data=body,headers=headers)