Assume we have the following arrays of objects to be compared based on property id
:
a = [{\'id\':\'1\', \'name\':\'a1\'}, {\'id\':\'2\', \'name\':\'
Here is a nice one line answer :)
Basically, you can filter, as you were trying to do already. Then you can also filter b for each a element and if the length of the filtered b is zero, then you return true because that means the a element is unique to a.
var a = [{
'id': '1',
'name': 'a1'
}, {
'id': '2',
'name': 'a2'
}, {
'id': '3',
'name': 'a3'
}];
var b = [{
'id': '2',
'name': 'a2'
}];
c = a.filter( x => !b.filter( y => y.id === x.id).length);
console.log(c);