Conditional Compile using Boost type-traits

Question

I have a template that I would like to conditionally compile depending on the type of the argument. I only care about differentiating between \"Plain Old Data\" (POD), i.e., in

Answer 1

You can do it without enable_if, because all you need is to dispatch depending on type traits. enable_if is used to add/remove template instantiations to/from overload resolution. You may want to use call traits to choose the best method to pass objects to your function. As a rule, objects should be passed by reference, whereas POD is passed by value. call_traits let's you choose between const and non-const references. The code below uses const reference.

#include 
#include 

template 
class foo {
public:
    void bar(typename boost::call_traits::param_type obj) {
        do_something(obj, boost::is_pod());
    }
private:
    void do_something(T obj, const boost::true_type&)
    {
      // do something for POD
    }
    void do_something(const T& obj, const boost::false_type&)
    {
      // do something for classes
    }
};