Dynamic Variable naming in r

Question

structure(list(Metrics = structure(c(1L, 2L, 3L, 4L, 5L, 6L, 
1L, 2L, 3L, 4L, 5L, 6L, 1L, 2L, 3L, 4L, 5L, 6L, 1L, 2L, 3L, 4L, 
5L, 6L), .Label = c(\"  LINESCOMM \", \"           


        

Answer 1

Why not just splitting the data.frame and working with list

dflist <- split(agg, agg$Project)
str(dflist)
## List of 4
 ## $   Demo_Architect :'data.frame':   6 obs. of  3 variables:
 ## $   Demo_May_10    :'data.frame':   6 obs. of  3 variables:
 ## $   Demo_May_14    :'data.frame':   6 obs. of  3 variables:
 ## $   NPP            :'data.frame':   6 obs. of  3 variables:

names(dflist) <- paste0("project", seq_along(dflist))

And if you really want to have the list elements (new dfs) in your global environment, you can use list2env.

list2env(dflist, .GlobalEnv)
ls()
## [1] "agg"      "dflist"   "project1" "project2" "project3"
## [6] "project4"

head(project3)
##            Metrics        Project    Value
## 13      LINESCOMM    Demo_May_14  1172.000
## 14   NCNBLOC_FILE    Demo_May_14  1500.000
## 15    RCYCLOMATIC    Demo_May_14   142.000
## 16           RISK    Demo_May_14     4.241
## 17      RMAXLEVEL    Demo_May_14    24.000
## 18      RNOEXSTAT    Demo_May_14    98.000

Just want to point out that it's generally safer to work with list by using lapply, sapply or for loop rather than using the global environment.

EDIT : If you want a different naming scheme

names(dflist) <- paste0("project_", gsub("\\s+", "", levels(agg$Project)))
list2env(dflist, .GlobalEnv)
ls()
## [1] "agg"                    "dflist"                
## [3] "project_Demo_Architect" "project_Demo_May_10"   
## [5] "project_Demo_May_14"    "project_NPP"