jQuery sortColumns plugin: How to sort correctly with rowspan

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北海茫月
北海茫月 2021-02-06 09:18

Following this post jQuery table sort (github link: https://github.com/padolsey/jQuery-Plugins/blob/master/sortElements/jquery.sortElements.js), I am successfully sort columns,

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  •  醉梦人生
    2021-02-06 09:35

    Conditions for the code to work:

    • Columns containing tds with rowspan must all be on the left of the table
    • All the tds in these columns must have a rowspan, even if it's 1
    • The groups of rows to sort are made with the rightmost of these columns (but it can easily be changed)

    jsFiddle: http://jsfiddle.net/5GrAC/77/

    var inverse = false;
    
    function sortColumn(index) {
        var trs = $('#resultsTable > tbody > tr'),
            nbRowspans = trs.first().children('[rowspan]').length,
            offset = trs.first().children('[rowspan]').last().offset().left;
    
        var tds = trs.children('[rowspan]').each(function() {
            $(this).data('row', $(this).parent().index());
            $(this).data('column', $(this).index());
            $(this).data('offset', $(this).offset().left)
        }).each(function() {
            if($(this).data('offset') != offset)
                return;
    
            var rowMin = $(this).data('row'),
                rowMax = rowMin + parseInt($(this).attr('rowspan'));
    
            trs.slice(rowMin, rowMax).children().filter(function() {
                return $(this).index() == index + $(this).parent().children('[rowspan]').length - nbRowspans;
            }).sortElements(function(a, b) {
                a = convertToNum($(a).text());
                b = convertToNum($(b).text());
    
                return (
                    isNaN(a) || isNaN(b) ?
                    a > b : +a > +b
                    ) ?
                inverse ? -1 : 1 :
                inverse ? 1 : -1;
            }, function() {
                return this.parentNode;
            });
        });
    
        var trs = $('#resultsTable > tbody > tr');
        tds.each(function() {
            if($(this).parent().index() != $(this).data('row'))
                $(this).insertBefore(trs.eq($(this).data('row')).children().eq($(this).data('column')));
        });
    
        inverse = !inverse;
    }
    

    Quick explanations:

    • Finding all tds with rowspan
    • Positions of these tds are saved, including left offset
    • These tds are filtered by their original offset to work only with the rightmost ones
    • trs related to each kept td are sorted using the wanted column
    • All tds with rowspan are finally moved back to their original position if necessary

    About question 2, I will only complete bartlaarhoven's answer by saying, the code can also be written like the following:

    return (
            (isNaN(a) || isNaN(b) ? a > b : +a > +b) ? 1 : -1
        ) * (inverse ? -1 : 1);
    

    You can easily read that inverse is used to inverse the result.

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