How to define string literal with character type that depends on template parameter?

Question

template
class StringTraits {
public:
    static const CharType NULL_CHAR = \'\\0\';
    static constexpr CharType* WHITESPACE_STR = \" \";
};

         


        

Answer 1

Here's an alternative implementation based on @zett42 's answer. Please advise me.

#include 
#include 

#define TOWSTRING_(x) L##x
#define TOWSTRING(x) TOWSTRING_(x)  
#define MAKE_LPCTSTR(C, STR) (std::get(std::tuple(STR, TOWSTRING(STR))))

template
class StringTraits {
public:
    static constexpr const CharType* WHITESPACE_STR = MAKE_LPCTSTR(CharType, "abc");
};

typedef StringTraits AStringTraits;
typedef StringTraits WStringTraits;

int main(int argc, char** argv) {
    std::cout << "Narrow string literal: " << AStringTraits::WHITESPACE_STR << std::endl;
    std::wcout << "Wide string literal  : " << WStringTraits::WHITESPACE_STR << std::endl;
    return 0;
}