I have gone through the sys
documentation, however there is something that is still unclear to me. I have looked for some similar question on stackoverflow, but I h
I suggest you use argparse (and here is the tutorial ). Saves you having to manually check for the existence of parameters. Moreover argparse gives you the --help
argument as a freebie, which will read the help=""
string defined for each argument, if provided.
In your case you have three mandatory (positional) argument and three optional ones. A sample argparse code would look like this:
#!/usr/bin/python
# coding: utf-8
import argparse
def parseArguments():
# Create argument parser
parser = argparse.ArgumentParser()
# Positional mandatory arguments
parser.add_argument("creditMom", help="Credit mom.", type=float)
parser.add_argument("creditDad", help="Credit dad.", type=float)
parser.add_argument("debtMom", help="Debt mom.", type=float)
# Optional arguments
parser.add_argument("-dD", "--debtDad", help="Debt dad.", type=float, default=1000.)
parser.add_argument("-s", "--salary", help="Debt dad.", type=float, default=2000.)
parser.add_argument("-b", "--bonus", help="Debt dad.", type=float, default=0.)
# Print version
parser.add_argument("--version", action="version", version='%(prog)s - Version 1.0')
# Parse arguments
args = parser.parse_args()
return args
def example(credit_mom, credit_dad, debt_mom, debt_dad = 1000, salary = 2000, bonus = 0):
total_gain = salary + credit_dad + credit_mom + bonus
total_loss = debt_dad + debt_mom
return total_gain - total_loss
if __name__ == '__main__':
# Parse the arguments
args = parseArguments()
# Raw print arguments
print("You are running the script with arguments: ")
for a in args.__dict__:
print(str(a) + ": " + str(args.__dict__[a]))
# Run function
print(example(args.creditMom, args.creditDad, args.debtMom, args.debtDad, args.salary, args.bonus))