I want a to be rounded to 13.95.
a
>>> a 13.949999999999999 >>> round(a, 2) 13.949999999999999
The ro
What about a lambda function like this:
arred = lambda x,n : x*(10**n)//1/(10**n)
This way you could just do:
arred(3.141591657,2)
and get
3.14