Convert integer to hex-string with specific format

Question

I am new to python and have following problem: I need to convert an integer to a hex string with 6 bytes.

e.g. 281473900746245 --> \"\\xFF\\xFF\\xBF\\xDE\\x16\\x05\"

Answer 1

In Python 3.2 or above, you can use the to_bytes() method of the interger.

>>> i = 281473900746245       
>>> i.to_bytes((i.bit_length() + 7) // 8, "big")
b'\xff\xff\xbf\xde\x16\x05'