Namedtuple like class

Question

I find myself writing this class often in my python code when I need a quick single use class.

class Struct(object):
   def __init__( self, **kwargs ):
      for          


        

Answer 1

From Python 3.3 and afterwards, you can use types.SimpleNamespace:

>>> import types
>>> foo = types.SimpleNamespace(bar='one', baz=1)
>>> print(foo.bar)
one
>>> foo.baz += 1
>>> foo.novo = 42

The builtin type is roughly equivalent to the following code:

class SimpleNamespace:

    def __init__(self, **kwargs):
        self.__dict__.update(kwargs)

    def __repr__(self):
        keys = sorted(self.__dict__)
        items = ("{}={!r}".format(k, self.__dict__[k]) for k in keys)
        return "{}({})".format(type(self).__name__, ", ".join(items))

    def __eq__(self, other):
        return self.__dict__ == other.__dict__

update

Starting with Python 3.7, you can use the dataclass module:

from dataclasses import dataclass, field

@dataclass
class Struct:
    bar: str = field(default='one')
    baz: int = field(default=1)

You can use this as follows:

foo = Struct( bar='one', baz=1 )
print(foo.bar)
foo.baz += 1
foo.novo = 42

By default, it incorporates equality testing and a nice looking repr:

>>> foo == Struct(bar='one', baz=2)
True
>>> foo
Struct(bar='one', baz=2)