How does the scipy distance_transform_edt function work?

Question

https://docs.scipy.org/doc/scipy-0.14.0/reference/generated/scipy.ndimage.morphology.distance_transform_edt.html

I\'m having trouble understanding how the Euclidean dist

Answer 1

Warren has already explained how distance_transform_edt works. In your case,you could change sampling units along x and y

ndimage.distance_transform_edt(a)
array([[ 0.,  0.,  0.,  0.,  0.],
       [ 0.,  1.,  0.,  0.,  0.],
       [ 0.,  0.,  0.,  0.,  0.],
       [ 0.,  0.,  0.,  1.,  0.],
       [ 0.,  0.,  0.,  0.,  0.]])

But

>>> ndimage.distance_transform_edt(a, sampling=[2,2])
array([[ 0.,  0.,  0.,  0.,  0.],
       [ 0.,  2.,  0.,  0.,  0.],
       [ 0.,  0.,  0.,  0.,  0.],
       [ 0.,  0.,  0.,  2.,  0.],
       [ 0.,  0.,  0.,  0.,  0.]])

Or

ndimage.distance_transform_edt(a, sampling=[3,3])
array([[ 0.,  0.,  0.,  0.,  0.],
       [ 0.,  3.,  0.,  0.,  0.],
       [ 0.,  0.,  0.,  0.,  0.],
       [ 0.,  0.,  0.,  3.,  0.],
       [ 0.,  0.,  0.,  0.,  0.]])