I\'m running this code with JDK 1.4 and 1.5 and get different results. Why is it the case?
String str = \"\";
int test = 3;
str = String.valueOf(test);
System.o
If you are using "==" operator on operation of String literals, then it depends on the whether the string literal value is present on "String Pool" or not, in your case variable "str" is a string JVM first checks on "String Pool" if it is found then it returns TRUE else FALSE. Try the following code with the intern() method, to make the string literal available on "String Pool"
String str = "";
int test = 3;
str = String.valueOf(test).intern();
System.out.println("str[" + str + "]\nequals result[" + (str == "3") + "]");
if (str == "3") {
System.out.println("if");
} else {
System.out.println("else");
}
according to documentation for intern() method: intern() method searches an internal table of strings for a string equal to this String. If the string is not in the table, it is added. Answers the string contained in the table which is equal to this String. The same string object is always answered for strings which are equal.
Well "==" operation is not recommended for string comparison. use equals() or equalsIgnoreCase() method().
I tried even in java 1.7 without intern() the output is
str[3]
equals result[false]
else
with intern() the output comes to:
str[3]
equals result[true]
if
This is not the problem of jdk 1.4 and 1.5 this is a "logical error".