What are the benefits to passing integral types by const ref

Question

The question: Is there benefit to passing an integral type by const reference as opposed to simply by value.

ie.

void foo(const int& n); // case #1
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Answer 1

well the cost of a reference is the same typically of that of an integral type, but with the reference you have an indirection that has to take place, because the reference to some memory has to be resolved into a value.

Just copy by value, stick to an immutable convention for built-in types.