How do i pass an array function without using pointers

Question

I have been asked in an interview how do you pass an array to a function without using any pointers but it seems to be impossible or there is way to do this?

Answer 1

simply pass the location of base element and then accept it as 'int a[]'. Here's an example:-

    main()
    {
        int a[]={0,1,2,3,4,5,6,7,8,9};
        display(a);
    }
    display(int a[])
    {
        int i;
        for(i=0;i<10;i++) printf("%d ",a[i]);
    }