i want to display the employee names which having names start with a and b ,it should be like list will display employees with \'a\' as a first letter and then the \'b\' as a
Regular expressions work well if needing to find a range of starting characters. The following finds all employee names starting with A, B, C or D and adds the “UPPER” call in case a name is in the database with a starting lowercase letter. My query works in Oracle (I did not test other DB's). The following would return for example:
Adams
adams
Dean
dean
This query also ignores case in the ORDER BY via the "lower" call:
SELECT employee_name
FROM employees
WHERE REGEXP_LIKE(UPPER(TRIM(employee_name)), '^[A-D]')
ORDER BY lower(employee_name)