find the elapsed time between two dates in oracle sql

Question

i need to find the difference between the time in the format hh:mm:ss

select msglog.id,max(msglog.timestamp) enddate,
   min(msglog.timestamp) startdate,
   en         


        

Answer 1

To get the diff in seconds you can use this

select round(24 * 60 * 60* (TO_DATE('2017/02/17 9:32:25', 'YYYY/MM/DD HH:MI:SS') - TO_DATE('2017/02/17 8:30:30', 'YYYY/MM/DD HH:MI:SS'))) from dual;