How to get words frequency in efficient way with ruby?

Question

Sample input:

\"I was 09809 home -- Yes! yes!  You was\"

and output:

{ \'yes\' => 2, \'was\' => 2, \'i\' => 1, \'home\         


        

Answer 1

This works, and ignores the numbers:

def get_words(my_str)
    my_str = my_str.scan(/\w+/)
    h = Hash.new(0)
    my_str.each do |s|
        s = s.downcase
        if s !~ /^[0-9]*\.?[0-9]+$/ 
            h[s] += 1
        end
    end
    return h
end

print get_words('I was there 1000 !')
puts '\n'